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x^2-180x-900=0
a = 1; b = -180; c = -900;
Δ = b2-4ac
Δ = -1802-4·1·(-900)
Δ = 36000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36000}=\sqrt{3600*10}=\sqrt{3600}*\sqrt{10}=60\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-60\sqrt{10}}{2*1}=\frac{180-60\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+60\sqrt{10}}{2*1}=\frac{180+60\sqrt{10}}{2} $
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